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Hunan Normal University
College of Information Science and Engineering
Who's in the Middle
Time Limit: 1000ms, Special Time Limit:2500ms, Memory Limit:65536KB
Total submit users: 33, Accepted users: 29
Problem 10543 : No special judgement
Problem description
  FJ is surveying his herd to find the most average cow. He wants to know how much milk this 'median' cow gives: half of the cows give as much or more than the median; half give as much or less.

Given an odd number of cows N (1 <= N < 10,000) and their milk output (1..1,000,000), find the median amount of milk given such that at least half the cows give the same amount of milk or more and at least half give the same or less.

Input
  * Line 1: A single integer N

* Lines 2..N+1: Each line contains a single integer that is the milk output of one cow.

Output
  * Line 1: A single integer that is the median milk output.

Sample Input
5
2
4
1
3
5
Sample Output
3
Judge Tips
  Five cows with milk outputs of 1..5 1 and 2 are below 3; 4 and 5 are above 3.

Problem Source
  USACO 2004 November test data by qshj

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